What is the answer to a=sqrt(24^2+20^2) ?

The answer to a=sqrt(24^2+20^2) is a=4sqrt(61)

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a=sqrt(24^2+20^2)

a = 2 4^{2} + 2 0^{2}

a = 461

Decimal Notation

a = 31.24099 \dots

Solution steps

a = 2 4^{2} + 2 0^{2}

Simplify

2 4^{2} + 2 0^{2} : 461

a = 461

\frac{2 ^{2}}{2 ^{- 2}}

1 < 4 x + 5 < 17

x \cdot 2 x

- \frac{3}{x} + 15 \leq 13

What is the answer to a=sqrt(24^2+20^2) ?
The answer to a=sqrt(24^2+20^2) is a=4sqrt(61)
Solve for a: a=sqrt(24^2+20^2)
The solution is a=4sqrt(61)