What is the answer to 5y-2(4-y)=27+1-2(2y-4)-1 ?

The answer to 5y-2(4-y)=27+1-2(2y-4)-1 is y= 43/11

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5y-2(4-y)=27+1-2(2y-4)-1

5 y - 2 (4 - y) = 27 + 1 - 2 (2 y - 4) - 1

y = \frac{43}{11}

Solution steps

5 y - 2 (4 - y) = 27 + 1 - 2 (2 y - 4) - 1

Expand

5 y - 2 (4 - y) : 7 y - 8

Expand

27 + 1 - 2 (2 y - 4) - 1 : - 4 y + 35

7 y - 8 = - 4 y + 35

Move

8

to the right side

7 y = - 4 y + 43

Move

4 y

to the left side

11 y = 43

Divide both sides by

11

y = \frac{43}{11}

\frac{1}{7} - x < 3

x^{2} + 12 x - 5 = 0

(\frac{4}{7})^{1}

9 x (a - b) - 2 y (a - b)

t^{4} - p^{4}

What is the answer to 5y-2(4-y)=27+1-2(2y-4)-1 ?
The answer to 5y-2(4-y)=27+1-2(2y-4)-1 is y= 43/11
Solve for y: 5y-2(4-y)=27+1-2(2y-4)-1
The solution is y= 43/11