What is x^2+2<= x^2+5x<= x^2+3 ?

The solution to x^2+2<= x^2+5x<= x^2+3 is 2/5 <= x<= 3/5

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x^2+2<= x^2+5x<= x^2+3

x^{2} + 2 \leq x^{2} + 5 x \leq x^{2} + 3

\frac{2}{5} \leq x \leq \frac{3}{5}

Interval Notation

[\frac{2}{5}, \frac{3}{5}]

Decimal Notation

0.4 \leq x \leq 0.6

Solution steps

x^{2} + 2 \leq x^{2} + 5 x \leq x^{2} + 3

a \leq u \leq b

then

a \leq u and u \leq b

x^{2} + 2 \leq x^{2} + 5 x and x^{2} + 5 x \leq x^{2} + 3

x^{2} + 2 \leq x^{2} + 5 x : x \geq \frac{2}{5}

x^{2} + 5 x \leq x^{2} + 3 : x \leq \frac{3}{5}

Combine the intervals

x \geq \frac{2}{5} and x \leq \frac{3}{5}

Merge Overlapping Intervals

\frac{2}{5} \leq x \leq \frac{3}{5}

\frac{1}{3} \cdot 0

\frac{1}{\frac{1}{7}}

8 x^{3} + 64

∣ 4 - 3 x ∣ = 12

18 - 3 (8 x + 4) \geq - 6 (4 x - 1)

What is x^2+2<= x^2+5x<= x^2+3 ?
The solution to x^2+2<= x^2+5x<= x^2+3 is 2/5 <= x<= 3/5