What are the solutions to the equation x^2-4x=11 ?

The solutions to the equation x^2-4x=11 are x=2+sqrt(15),x=2-sqrt(15)

Find the zeros of x^2-4x=11

The zeros of x^2-4x=11 are x=2+sqrt(15),x=2-sqrt(15)

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x^{2} - 4 x = 11

x = 2 + 15, x = 2 - 15

Decimal Notation

x = 5.87298 \dots, x = - 1.87298 \dots

Solution steps

x^{2} - 4 x = 11

Move

11

to the left side

x^{2} - 4 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 11) = 215

x_{1, 2} = \frac{- ( - 4 ) \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 15}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 15}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 15}{2 \cdot 1} : 2 + 15

x = \frac{- ( - 4 ) - 2 15}{2 \cdot 1} : 2 - 15

The solutions to the quadratic equation are:

x = 2 + 15, x = 2 - 15

(- 4 x^{2} y)^{4}

\frac{1}{2} + \frac{1}{5}

1 0^{\frac{5}{3}}

- \frac{3}{5} (25 s - 40) = 6 s - 18

4 x^{3} - 24 x^{2}

What are the solutions to the equation x^2-4x=11 ?
The solutions to the equation x^2-4x=11 are x=2+sqrt(15),x=2-sqrt(15)
Find the zeros of x^2-4x=11
The zeros of x^2-4x=11 are x=2+sqrt(15),x=2-sqrt(15)