What are the solutions to the equation (x-10)(x-2)=-16 ?

The solutions to the equation (x-10)(x-2)=-16 are x=6

Find the zeros of (x-10)(x-2)=-16

The zeros of (x-10)(x-2)=-16 are x=6

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(x - 10) (x - 2) = - 16

x = 6

Solution steps

(x - 10) (x - 2) = - 16

Expand

(x - 10) (x - 2) : x^{2} - 12 x + 20

x^{2} - 12 x + 20 = - 16

Move

16

to the left side

x^{2} - 12 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 12 )}{2 \cdot 1}

\frac{- ( - 12 )}{2 \cdot 1} = 6

x = 6

The solution to the quadratic equation is:

x = 6

2 z^{2} - 22 = 0

6 (x - 5) (x - 4) < 0

6 x + 5 < - 25

\frac{( x + 5 ) ( 2 x - 7 )}{( x + 1 ) ^{2}} \leq 0

u^{2} - 10 u + 25

What are the solutions to the equation (x-10)(x-2)=-16 ?
The solutions to the equation (x-10)(x-2)=-16 are x=6
Find the zeros of (x-10)(x-2)=-16
The zeros of (x-10)(x-2)=-16 are x=6