What are the solutions to the equation 3x^2-22x+39=0 ?

The solutions to the equation 3x^2-22x+39=0 are x= 13/3 ,x=3

Find the zeros of 3x^2-22x+39=0

The zeros of 3x^2-22x+39=0 are x= 13/3 ,x=3

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3 x^{2} - 22 x + 39 = 0

x = \frac{13}{3}, x = 3

Decimal Notation

x = 4.33333 \dots, x = 3

Solution steps

3 x^{2} - 22 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 3 \cdot 39}{2 \cdot 3}

(- 22)^{2} - 4 \cdot 3 \cdot 39 = 4

x_{1, 2} = \frac{- ( - 22 ) \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 22 ) - 4}{2 \cdot 3}

x = \frac{- ( - 22 ) + 4}{2 \cdot 3} : \frac{13}{3}

x = \frac{- ( - 22 ) - 4}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

x = \frac{13}{3}, x = 3

- 4 T + 8 - 6 T = - 4 - 10 T + 3

(x \cdot y)^{\frac{3}{4}}

\frac{x}{- 7} < 14

10 \cdot 972

36 t^{2} - 1

What are the solutions to the equation 3x^2-22x+39=0 ?
The solutions to the equation 3x^2-22x+39=0 are x= 13/3 ,x=3
Find the zeros of 3x^2-22x+39=0
The zeros of 3x^2-22x+39=0 are x= 13/3 ,x=3