What is the answer to |w^2-4|=3 ?

The answer to |w^2-4|=3 is w=-sqrt(7)\lor w=-1\lor w=1\lor w=sqrt(7)

Solve for w: |w^2-4|=3

The solution is w=-sqrt(7)\lor w=-1\lor w=1\lor w=sqrt(7)

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Popular >

w^{2} - 4 = 3

w = - 7 or w = - 1 or w = 1 or w = 7

Decimal Notation

w = - 2.64575 \dots, w = - 1, w = 1, w = 2.64575 \dots

Solution steps

w^{2} - 4 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

w^{2} - 4 = - 3 or w^{2} - 4 = 3

w^{2} - 4 = - 3 or w^{2} - 4 = 3

(w = - 1 or w = 1) or (w = - 7 or w = 7)

w = - 7 or w = - 1 or w = 1 or w = 7

\frac{3}{8} \cdot 8

∣ - 8 x + 5 ∣ \geq 12

48 \cdot 3

\frac{7}{7}

(\frac{3}{4} - \frac{3 i}{4})^{- 4}

What is the answer to |w^2-4|=3 ?
The answer to |w^2-4|=3 is w=-sqrt(7)\lor w=-1\lor w=1\lor w=sqrt(7)
Solve for w: |w^2-4|=3
The solution is w=-sqrt(7)\lor w=-1\lor w=1\lor w=sqrt(7)