What is sqrt(x^2-25)>0 ?

The solution to sqrt(x^2-25)>0 is x 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(x^2-25)>0

x^{2} - 25 > 0

x < - 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (5, \infty)

Solution steps

x^{2} - 25 > 0

Square both sides

(x^{2} - 25)^{2} > 0^{2}

Simplify

x^{2} - 25 > 0

x^{2} - 25 > 0 : x < - 5 or x > 5

x < - 5 or x > 5

Find singularity points

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

Combine the intervals

(x < - 5 or x > 5) and (x \leq - 5 or x \geq 5)

Merge Overlapping Intervals

x < - 5 or x > 5

\frac{x + 1}{x - 1} < 1

7 x + 1 = 3 x + 17

1.86 \cdot 2

3 x^{2} - 6 x + 6 = 0

\frac{3}{5} = 4 m