What are the solutions to the equation y^2+y-1=0 ?

The solutions to the equation y^2+y-1=0 are y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2

Find the zeros of y^2+y-1=0

The zeros of y^2+y-1=0 are y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + y - 1 = 0

y = \frac{- 1 + 5}{2}, y = \frac{- 1 - 5}{2}

Decimal Notation

y = 0.61803 \dots, y = - 1.61803 \dots

Solution steps

y^{2} + y - 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 1) = 5

y_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 1 + 5}{2 \cdot 1}, y_{2} = \frac{- 1 - 5}{2 \cdot 1}

y = \frac{- 1 + 5}{2 \cdot 1} : \frac{- 1 + 5}{2}

y = \frac{- 1 - 5}{2 \cdot 1} : \frac{- 1 - 5}{2}

The solutions to the quadratic equation are:

y = \frac{- 1 + 5}{2}, y = \frac{- 1 - 5}{2}

1764

10 < 3 x + 19

2 a + 2 b + a v + b v

5 x + 26 = x - 2

4 x^{2} + x + 3 = 0

What are the solutions to the equation y^2+y-1=0 ?
The solutions to the equation y^2+y-1=0 are y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2
Find the zeros of y^2+y-1=0
The zeros of y^2+y-1=0 are y=(-1+sqrt(5))/2 ,y=(-1-sqrt(5))/2