What are the solutions to the equation 3x^2+18x+32=5 ?

The solutions to the equation 3x^2+18x+32=5 are x=-3

Find the zeros of 3x^2+18x+32=5

The zeros of 3x^2+18x+32=5 are x=-3

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3 x^{2} + 18 x + 32 = 5

x = - 3

Solution steps

3 x^{2} + 18 x + 32 = 5

Move

5

to the left side

3 x^{2} + 18 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 27 = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 3}

x = \frac{- 18}{2 \cdot 3}

\frac{- 18}{2 \cdot 3} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

x^{4} - 3 x^{3} + 2 x^{2} > 0

3 x^{2} + x - 14

3147

∣ x - 9 ∣ < 3

3 a + 7 = a + 9

What are the solutions to the equation 3x^2+18x+32=5 ?
The solutions to the equation 3x^2+18x+32=5 are x=-3
Find the zeros of 3x^2+18x+32=5
The zeros of 3x^2+18x+32=5 are x=-3