What are the solutions to the equation 3x^2+x+10=3 ?

The solutions to the equation 3x^2+x+10=3 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6

Find the zeros of 3x^2+x+10=3

The zeros of 3x^2+x+10=3 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + x + 10 = 3

x = - \frac{1}{6} + i \frac{83}{6}, x = - \frac{1}{6} - i \frac{83}{6}

Solution steps

3 x^{2} + x + 10 = 3

Move

3

to the left side

3 x^{2} + x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

1^{2} - 4 \cdot 3 \cdot 7 : 83 i

x_{1, 2} = \frac{- 1 \pm 83 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 83 i}{2 \cdot 3}, x_{2} = \frac{- 1 - 83 i}{2 \cdot 3}

x = \frac{- 1 + 83 i}{2 \cdot 3} : - \frac{1}{6} + i \frac{83}{6}

x = \frac{- 1 - 83 i}{2 \cdot 3} : - \frac{1}{6} - i \frac{83}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{83}{6}, x = - \frac{1}{6} - i \frac{83}{6}

k^{2} - 7 k

\frac{3 ^{\frac{1}{3}}}{3 ^{\frac{7}{3}}}

3 g^{2} - 7 g + 2

x = 0.1572 \cdot 0.0 5^{2} \cdot 0. 1^{2}

- 12 = - 9 w

What are the solutions to the equation 3x^2+x+10=3 ?
The solutions to the equation 3x^2+x+10=3 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6
Find the zeros of 3x^2+x+10=3
The zeros of 3x^2+x+10=3 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6