What are the solutions to the equation 2^2+b^2=5^2 ?

The solutions to the equation 2^2+b^2=5^2 are b=sqrt(21),b=-sqrt(21)

Find the zeros of 2^2+b^2=5^2

The zeros of 2^2+b^2=5^2 are b=sqrt(21),b=-sqrt(21)

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2^{2} + b^{2} = 5^{2}

b = 21, b = - 21

Decimal Notation

b = 4.58257 \dots, b = - 4.58257 \dots

Solution steps

2^{2} + b^{2} = 5^{2}

Move

2^{2}

to the right side

b^{2} = 21

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 21, b = - 21

1221 + 2014

\frac{x}{5} = 5

x^{2} - 14 x + 33

12 - 2 k = 5

3 x + 7 + 2 x = x + 12 - 8

What are the solutions to the equation 2^2+b^2=5^2 ?
The solutions to the equation 2^2+b^2=5^2 are b=sqrt(21),b=-sqrt(21)
Find the zeros of 2^2+b^2=5^2
The zeros of 2^2+b^2=5^2 are b=sqrt(21),b=-sqrt(21)