What are the solutions to the equation -11x^2+26x+61=0 ?

The solutions to the equation -11x^2+26x+61=0 are x=-(-13+2sqrt(210))/(11),x=(13+2sqrt(210))/(11)

Find the zeros of -11x^2+26x+61=0

The zeros of -11x^2+26x+61=0 are x=-(-13+2sqrt(210))/(11),x=(13+2sqrt(210))/(11)

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- 11 x^{2} + 26 x + 61 = 0

x = - \frac{- 13 + 2 210}{11}, x = \frac{13 + 2 210}{11}

Decimal Notation

x = - 1.45297 \dots, x = 3.81661 \dots

Solution steps

- 11 x^{2} + 26 x + 61 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 ( - 11 ) \cdot 61}{2 ( - 11 )}

2 6^{2} - 4 (- 11) \cdot 61 = 4210

x_{1, 2} = \frac{- 26 \pm 4 210}{2 ( - 11 )}

Separate the solutions

x_{1} = \frac{- 26 + 4 210}{2 ( - 11 )}, x_{2} = \frac{- 26 - 4 210}{2 ( - 11 )}

x = \frac{- 26 + 4 210}{2 ( - 11 )} : - \frac{- 13 + 2 210}{11}

x = \frac{- 26 - 4 210}{2 ( - 11 )} : \frac{13 + 2 210}{11}

The solutions to the quadratic equation are:

x = - \frac{- 13 + 2 210}{11}, x = \frac{13 + 2 210}{11}

\frac{8 x + 4}{15} = \frac{9 x + 7}{7} - 6

∣ x - 5 ∣ \leq 4

(8.8 - x)^{2} = 8. 8^{2} - x^{2}

\frac{z}{- 1} \leq - 2

3 x^{2} - 7 x - 1 = 0

What are the solutions to the equation -11x^2+26x+61=0 ?
The solutions to the equation -11x^2+26x+61=0 are x=-(-13+2sqrt(210))/(11),x=(13+2sqrt(210))/(11)
Find the zeros of -11x^2+26x+61=0
The zeros of -11x^2+26x+61=0 are x=-(-13+2sqrt(210))/(11),x=(13+2sqrt(210))/(11)