v^2-6v-27=0

解

v^{2} - 6 v - 27 = 0

v = 9, v = - 3

解答ステップ

v^{2} - 6 v - 27 = 0

解くとthe二次式

v_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 27) = 12

v_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 \cdot 1}

解を分離する

v_{1} = \frac{- ( - 6 ) + 12}{2 \cdot 1}, v_{2} = \frac{- ( - 6 ) - 12}{2 \cdot 1}

v = \frac{- ( - 6 ) + 12}{2 \cdot 1} : 9

v = \frac{- ( - 6 ) - 12}{2 \cdot 1} : - 3

二次equationの解:

v = 9, v = - 3