What are the solutions to the equation 6q^2-10q=2 ?

The solutions to the equation 6q^2-10q=2 are q=(5+sqrt(37))/6 ,q=(5-sqrt(37))/6

Find the zeros of 6q^2-10q=2

The zeros of 6q^2-10q=2 are q=(5+sqrt(37))/6 ,q=(5-sqrt(37))/6

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6 q^{2} - 10 q = 2

q = \frac{5 + 37}{6}, q = \frac{5 - 37}{6}

Decimal Notation

q = 1.84712 \dots, q = - 0.18046 \dots

Solution steps

6 q^{2} - 10 q = 2

Move

2

to the left side

6 q^{2} - 10 q - 2 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 10)^{2} - 4 \cdot 6 (- 2) = 237

q_{1, 2} = \frac{- ( - 10 ) \pm 2 37}{2 \cdot 6}

Separate the solutions

q_{1} = \frac{- ( - 10 ) + 2 37}{2 \cdot 6}, q_{2} = \frac{- ( - 10 ) - 2 37}{2 \cdot 6}

q = \frac{- ( - 10 ) + 2 37}{2 \cdot 6} : \frac{5 + 37}{6}

q = \frac{- ( - 10 ) - 2 37}{2 \cdot 6} : \frac{5 - 37}{6}

The solutions to the quadratic equation are:

q = \frac{5 + 37}{6}, q = \frac{5 - 37}{6}

8 x + 78 = 2 x + 114

∣ x ∣ \leq 10

\frac{3}{x} + \frac{5}{y}

2 k^{2} - 11 k + 15

\frac{x ^{- 1}}{x ^{- 2} + y ^{- 8}}

What are the solutions to the equation 6q^2-10q=2 ?
The solutions to the equation 6q^2-10q=2 are q=(5+sqrt(37))/6 ,q=(5-sqrt(37))/6
Find the zeros of 6q^2-10q=2
The zeros of 6q^2-10q=2 are q=(5+sqrt(37))/6 ,q=(5-sqrt(37))/6