What is ((80x^4))/(y^3)*(xy)/(5x^2) ?

The solution to ((80x^4))/(y^3)*(xy)/(5x^2) is (16x^3)/(y^2)

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simplify ((80x^4))/(y^3)*(xy)/(5x^2)

simplify

\frac{( 80 x ^{4} )}{y ^{3}} \cdot \frac{x y}{5 x ^{2}}

\frac{16 x ^{3}}{y ^{2}}

Solution steps

\frac{80 x ^{4}}{y ^{3}} \cdot \frac{x y}{5 x ^{2}}

Cancel

\frac{x y}{5 x ^{2}} : \frac{y}{5 x}

= \frac{80 x ^{4}}{y ^{3}} \cdot \frac{y}{5 x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{80 x ^{4} y}{y ^{3} \cdot 5 x}

Factor the number:

80 = 5 \cdot 16

= \frac{5 \cdot 16 x ^{4} y}{y ^{3} \cdot 5 x}

Cancel the common factor:

5

= \frac{16 x ^{4} y}{y ^{3} x}

Simplify

\frac{x ^{4}}{x} : x^{3}

= \frac{16 x ^{3} y}{y ^{3}}

Simplify

\frac{y}{y ^{3}} : \frac{1}{y ^{2}}

= \frac{16 x ^{3}}{y ^{2}}

8 u + 1 + 11 = 12

\frac{3}{4} - \frac{5}{12}

8 a^{3} - 6 a^{2} + 3 - 4 a

2 x^{3} - 8 x^{2} - x + 4

(53)^{2}

What is ((80x^4))/(y^3)*(xy)/(5x^2) ?
The solution to ((80x^4))/(y^3)*(xy)/(5x^2) is (16x^3)/(y^2)