What are the solutions to the equation x^2+6x+9=2 ?

The solutions to the equation x^2+6x+9=2 are x=-3+sqrt(2),x=-3-sqrt(2)

Find the zeros of x^2+6x+9=2

The zeros of x^2+6x+9=2 are x=-3+sqrt(2),x=-3-sqrt(2)

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x^{2} + 6 x + 9 = 2

x = - 3 + 2, x = - 3 - 2

Decimal Notation

x = - 1.58578 \dots, x = - 4.41421 \dots

Solution steps

x^{2} + 6 x + 9 = 2

Move

2

to the left side

x^{2} + 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 7 = 22

x_{1, 2} = \frac{- 6 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 2}{2 \cdot 1}

x = \frac{- 6 + 2 2}{2 \cdot 1} : - 3 + 2

x = \frac{- 6 - 2 2}{2 \cdot 1} : - 3 - 2

The solutions to the quadratic equation are:

x = - 3 + 2, x = - 3 - 2

\frac{6 x ^{3} - 13 x ^{2} - 5 x}{x ^{2} - 4} \geq 0

\frac{1}{2 \cdot 1 0 ^{9}}

\frac{1}{\frac{1}{8}}

lo g_{e} (3)

(x - 8) (x - 4) (x - 2) > 0

What are the solutions to the equation x^2+6x+9=2 ?
The solutions to the equation x^2+6x+9=2 are x=-3+sqrt(2),x=-3-sqrt(2)
Find the zeros of x^2+6x+9=2
The zeros of x^2+6x+9=2 are x=-3+sqrt(2),x=-3-sqrt(2)