What are the solutions to the equation x^2+8x-19=0 ?

The solutions to the equation x^2+8x-19=0 are x=-4+sqrt(35),x=-4-sqrt(35)

Find the zeros of x^2+8x-19=0

The zeros of x^2+8x-19=0 are x=-4+sqrt(35),x=-4-sqrt(35)

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x^{2} + 8 x - 19 = 0

x = - 4 + 35, x = - 4 - 35

Decimal Notation

x = 1.91607 \dots, x = - 9.91607 \dots

Solution steps

x^{2} + 8 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 19) = 235

x_{1, 2} = \frac{- 8 \pm 2 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 35}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 35}{2 \cdot 1}

x = \frac{- 8 + 2 35}{2 \cdot 1} : - 4 + 35

x = \frac{- 8 - 2 35}{2 \cdot 1} : - 4 - 35

The solutions to the quadratic equation are:

x = - 4 + 35, x = - 4 - 35

2 a^{2} - 18 = 0

(x^{\frac{1}{2}})^{\frac{5}{6}}

33 + 4 x \leq - (x + 7)

(x - 2)^{2} = - 4

\frac{3 x ^{5} y}{12 x ^{3} y ^{2}}

What are the solutions to the equation x^2+8x-19=0 ?
The solutions to the equation x^2+8x-19=0 are x=-4+sqrt(35),x=-4-sqrt(35)
Find the zeros of x^2+8x-19=0
The zeros of x^2+8x-19=0 are x=-4+sqrt(35),x=-4-sqrt(35)