What are the solutions to the equation 8x^2+2x+1=0 ?

The solutions to the equation 8x^2+2x+1=0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8

Find the zeros of 8x^2+2x+1=0

The zeros of 8x^2+2x+1=0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8

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8 x^{2} + 2 x + 1 = 0

x = - \frac{1}{8} + i \frac{7}{8}, x = - \frac{1}{8} - i \frac{7}{8}

Solution steps

8 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

Simplify

2^{2} - 4 \cdot 8 \cdot 1 : 27 i

x_{1, 2} = \frac{- 2 \pm 2 7 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 2 + 2 7 i}{2 \cdot 8}, x_{2} = \frac{- 2 - 2 7 i}{2 \cdot 8}

x = \frac{- 2 + 2 7 i}{2 \cdot 8} : - \frac{1}{8} + i \frac{7}{8}

x = \frac{- 2 - 2 7 i}{2 \cdot 8} : - \frac{1}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = - \frac{1}{8} + i \frac{7}{8}, x = - \frac{1}{8} - i \frac{7}{8}

\frac{x - 7}{x + 8} \leq 0

12 x^{2} + 34 x - 28

∣ w - 100 ∣ \leq 400

4 = 0.5 \cdot 4000 \cdot x^{2} - 0.5 \cdot 4000 (- 0.02)^{2}

A = 6500 (1 + \frac{0.06}{360})^{3603}

What are the solutions to the equation 8x^2+2x+1=0 ?
The solutions to the equation 8x^2+2x+1=0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8
Find the zeros of 8x^2+2x+1=0
The zeros of 8x^2+2x+1=0 are x=-1/8+i(sqrt(7))/8 ,x=-1/8-i(sqrt(7))/8