What are the solutions to the equation 1/7 (x+3)^2=7 ?

The solutions to the equation 1/7 (x+3)^2=7 are x=4,x=-10

Find the zeros of 1/7 (x+3)^2=7

The zeros of 1/7 (x+3)^2=7 are x=4,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{7} (x + 3)^{2} = 7

x = 4, x = - 10

Solution steps

\frac{1}{7} (x + 3)^{2} = 7

Multiply both sides by

7

(x + 3)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 49 : x = 4

Solve

x + 3 = - 49 : x = - 10

The solutions to the quadratic equation are:

x = 4, x = - 10

- \frac{3}{4} - 2

4 x + 8 < 32

x^{2} + 0 x + 2 = 9

x (x + 1) (x + 3) (x + 5) - x (x + 3) (x + 5)

2 - (- 5)

What are the solutions to the equation 1/7 (x+3)^2=7 ?
The solutions to the equation 1/7 (x+3)^2=7 are x=4,x=-10
Find the zeros of 1/7 (x+3)^2=7
The zeros of 1/7 (x+3)^2=7 are x=4,x=-10