What are the solutions to the equation n^2+2n-46=2 ?

The solutions to the equation n^2+2n-46=2 are n=6,n=-8

Find the zeros of n^2+2n-46=2

The zeros of n^2+2n-46=2 are n=6,n=-8

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n^{2} + 2 n - 46 = 2

n = 6, n = - 8

Solution steps

n^{2} + 2 n - 46 = 2

Move

2

to the left side

n^{2} + 2 n - 48 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 48) = 14

n_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 2 + 14}{2 \cdot 1}, n_{2} = \frac{- 2 - 14}{2 \cdot 1}

n = \frac{- 2 + 14}{2 \cdot 1} : 6

n = \frac{- 2 - 14}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

n = 6, n = - 8

\frac{1}{\frac{1}{100}}

- 1 \geq 1 - h

\frac{2}{3} - \frac{2}{3}

x e^{- (\frac{1}{4})} = 2

6 x^{2} - 2 x + 1 = 0

What are the solutions to the equation n^2+2n-46=2 ?
The solutions to the equation n^2+2n-46=2 are n=6,n=-8
Find the zeros of n^2+2n-46=2
The zeros of n^2+2n-46=2 are n=6,n=-8