What are the solutions to the equation 2m^2-m-6=0 ?

The solutions to the equation 2m^2-m-6=0 are m=2,m=-3/2

Find the zeros of 2m^2-m-6=0

The zeros of 2m^2-m-6=0 are m=2,m=-3/2

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2 m^{2} - m - 6 = 0

m = 2, m = - \frac{3}{2}

Decimal Notation

m = 2, m = - 1.5

Solution steps

2 m^{2} - m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 6) = 7

m_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 2}, m_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 2}

m = \frac{- ( - 1 ) + 7}{2 \cdot 2} : 2

m = \frac{- ( - 1 ) - 7}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

m = 2, m = - \frac{3}{2}

- 2 x^{2} + 4 = 0

\frac{4}{3} \cdot \frac{4}{3} \cdot \frac{4}{3}

2 m^{2} - 50

90 = s + \frac{s ^{2}}{10}

- x + 4 < \frac{1}{2} x + 1

What are the solutions to the equation 2m^2-m-6=0 ?
The solutions to the equation 2m^2-m-6=0 are m=2,m=-3/2
Find the zeros of 2m^2-m-6=0
The zeros of 2m^2-m-6=0 are m=2,m=-3/2