What are the solutions to the equation x^2+6=4x ?

The solutions to the equation x^2+6=4x are x=2+sqrt(2)i,x=2-sqrt(2)i

Find the zeros of x^2+6=4x

The zeros of x^2+6=4x are x=2+sqrt(2)i,x=2-sqrt(2)i

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x^{2} + 6 = 4 x

x = 2 + 2 i, x = 2 - 2 i

Solution steps

x^{2} + 6 = 4 x

Move

4 x

to the left side

x^{2} + 6 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 6 : 22 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 1} : 2 + 2 i

x = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 1} : 2 - 2 i

The solutions to the quadratic equation are:

x = 2 + 2 i, x = 2 - 2 i

x^{4} - 74 x^{2} + 1225

(3 x + 4)^{2} = 5

(4 x + 5) (x + 1) = 0

ln (4) = x

4 m^{2} - 4 m + 1

What are the solutions to the equation x^2+6=4x ?
The solutions to the equation x^2+6=4x are x=2+sqrt(2)i,x=2-sqrt(2)i
Find the zeros of x^2+6=4x
The zeros of x^2+6=4x are x=2+sqrt(2)i,x=2-sqrt(2)i