What are the solutions to the equation x^2-9x+5=0 ?

The solutions to the equation x^2-9x+5=0 are x=(9+sqrt(61))/2 ,x=(9-sqrt(61))/2

Find the zeros of x^2-9x+5=0

The zeros of x^2-9x+5=0 are x=(9+sqrt(61))/2 ,x=(9-sqrt(61))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 9 x + 5 = 0

x = \frac{9 + 61}{2}, x = \frac{9 - 61}{2}

Decimal

x = 8.40512 \dots, x = 0.59487 \dots

Solution steps

x^{2} - 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 5 = 61

x_{1, 2} = \frac{- ( - 9 ) \pm 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 61}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 61}{2 \cdot 1}

x = \frac{- ( - 9 ) + 61}{2 \cdot 1} : \frac{9 + 61}{2}

x = \frac{- ( - 9 ) - 61}{2 \cdot 1} : \frac{9 - 61}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 61}{2}, x = \frac{9 - 61}{2}

(e^{- 3 x})^{2}

(6 - 2 i) (6 + 2 i)

4 x + 3 (4 x + 7) = 4 (7 x + 3) - 3

7 x^{2} - 2 = - 65

m^{2} x + 6 m x n + 8 n^{2} x

What are the solutions to the equation x^2-9x+5=0 ?
The solutions to the equation x^2-9x+5=0 are x=(9+sqrt(61))/2 ,x=(9-sqrt(61))/2
Find the zeros of x^2-9x+5=0
The zeros of x^2-9x+5=0 are x=(9+sqrt(61))/2 ,x=(9-sqrt(61))/2