What are the solutions to the equation -x^2-4x-9=0 ?

The solutions to the equation -x^2-4x-9=0 are x=-2-sqrt(5)i,x=-2+sqrt(5)i

Find the zeros of -x^2-4x-9=0

The zeros of -x^2-4x-9=0 are x=-2-sqrt(5)i,x=-2+sqrt(5)i

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- x^{2} - 4 x - 9 = 0

x = - 2 - 5 i, x = - 2 + 5 i

Solution steps

- x^{2} - 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

Simplify

(- 4)^{2} - 4 (- 1) (- 9) : 25 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 5 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 5 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2 5 i}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2 5 i}{2 ( - 1 )} : - 2 - 5 i

x = \frac{- ( - 4 ) - 2 5 i}{2 ( - 1 )} : - 2 + 5 i

The solutions to the quadratic equation are:

x = - 2 - 5 i, x = - 2 + 5 i

78 = 18 - 5 y

x^{2} + 7 x + 6

- 9 = x + 3

3 x^{2} - 5 x \geq 4 x^{2} + 6

5 (x - 3) + 4 (x + 3) = 3 (x - 1)

What are the solutions to the equation -x^2-4x-9=0 ?
The solutions to the equation -x^2-4x-9=0 are x=-2-sqrt(5)i,x=-2+sqrt(5)i
Find the zeros of -x^2-4x-9=0
The zeros of -x^2-4x-9=0 are x=-2-sqrt(5)i,x=-2+sqrt(5)i