What are the solutions to the equation 12x^2+12x=0 ?

The solutions to the equation 12x^2+12x=0 are x=0,x=-1

Find the zeros of 12x^2+12x=0

The zeros of 12x^2+12x=0 are x=0,x=-1

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12 x^{2} + 12 x = 0

x = 0, x = - 1

Solution steps

12 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

1 2^{2} - 4 \cdot 12 \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 \cdot 12}, x_{2} = \frac{- 12 - 12}{2 \cdot 12}

x = \frac{- 12 + 12}{2 \cdot 12} : 0

x = \frac{- 12 - 12}{2 \cdot 12} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

2 x - 4 = - 6

x 2 = 30

lo g_{27} (81)

(\frac{4}{3})^{1}

- 4 g^{2} - 68 g = 172

What are the solutions to the equation 12x^2+12x=0 ?
The solutions to the equation 12x^2+12x=0 are x=0,x=-1
Find the zeros of 12x^2+12x=0
The zeros of 12x^2+12x=0 are x=0,x=-1