What are the solutions to the equation 2x^2-12x-6=0 ?

The solutions to the equation 2x^2-12x-6=0 are x=3+2sqrt(3),x=3-2sqrt(3)

Find the zeros of 2x^2-12x-6=0

The zeros of 2x^2-12x-6=0 are x=3+2sqrt(3),x=3-2sqrt(3)

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2 x^{2} - 12 x - 6 = 0

x = 3 + 23, x = 3 - 23

Decimal Notation

x = 6.46410 \dots, x = - 0.46410 \dots

Solution steps

2 x^{2} - 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 6) = 83

x_{1, 2} = \frac{- ( - 12 ) \pm 8 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 3}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 8 3}{2 \cdot 2}

x = \frac{- ( - 12 ) + 8 3}{2 \cdot 2} : 3 + 23

x = \frac{- ( - 12 ) - 8 3}{2 \cdot 2} : 3 - 23

The solutions to the quadratic equation are:

x = 3 + 23, x = 3 - 23

\frac{1}{81} p - 16 p^{5}

\frac{x ^{- 1} x ^{- 1}}{y ^{6} y ^{- 4}}

3 a (a + b + c) - 2 b (a + b + c) - c (a + b + c)

2 - x > 3

4^{\frac{- 3}{2}}

What are the solutions to the equation 2x^2-12x-6=0 ?
The solutions to the equation 2x^2-12x-6=0 are x=3+2sqrt(3),x=3-2sqrt(3)
Find the zeros of 2x^2-12x-6=0
The zeros of 2x^2-12x-6=0 are x=3+2sqrt(3),x=3-2sqrt(3)