What are the solutions to the equation 2x^2+9x=-5 ?

The solutions to the equation 2x^2+9x=-5 are x=(-9+sqrt(41))/4 ,x=(-9-sqrt(41))/4

Find the zeros of 2x^2+9x=-5

The zeros of 2x^2+9x=-5 are x=(-9+sqrt(41))/4 ,x=(-9-sqrt(41))/4

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2 x^{2} + 9 x = - 5

x = \frac{- 9 + 41}{4}, x = \frac{- 9 - 41}{4}

Decimal Notation

x = - 0.64921 \dots, x = - 3.85078 \dots

Solution steps

2 x^{2} + 9 x = - 5

Move

5

to the left side

2 x^{2} + 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 5 = 41

x_{1, 2} = \frac{- 9 \pm 41}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 41}{2 \cdot 2}, x_{2} = \frac{- 9 - 41}{2 \cdot 2}

x = \frac{- 9 + 41}{2 \cdot 2} : \frac{- 9 + 41}{4}

x = \frac{- 9 - 41}{2 \cdot 2} : \frac{- 9 - 41}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 41}{4}, x = \frac{- 9 - 41}{4}

4 x + 2 = x + 7

4 (2 m + 5) - 7 = 5 (m + 5)

3 x^{2} + 4 x - 5 = 0

3 w^{2} - 11 w = - 6

- 10 + 2 x - 4 x = - 24

What are the solutions to the equation 2x^2+9x=-5 ?
The solutions to the equation 2x^2+9x=-5 are x=(-9+sqrt(41))/4 ,x=(-9-sqrt(41))/4
Find the zeros of 2x^2+9x=-5
The zeros of 2x^2+9x=-5 are x=(-9+sqrt(41))/4 ,x=(-9-sqrt(41))/4