What are the solutions to the equation -4x^2-15x+4=0 ?

The solutions to the equation -4x^2-15x+4=0 are x=-4,x= 1/4

Find the zeros of -4x^2-15x+4=0

The zeros of -4x^2-15x+4=0 are x=-4,x= 1/4

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- 4 x^{2} - 15 x + 4 = 0

x = - 4, x = \frac{1}{4}

Decimal Notation

x = - 4, x = 0.25

Solution steps

- 4 x^{2} - 15 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 ( - 4 ) \cdot 4}{2 ( - 4 )}

(- 15)^{2} - 4 (- 4) \cdot 4 = 17

x_{1, 2} = \frac{- ( - 15 ) \pm 17}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 17}{2 ( - 4 )}, x_{2} = \frac{- ( - 15 ) - 17}{2 ( - 4 )}

x = \frac{- ( - 15 ) + 17}{2 ( - 4 )} : - 4

x = \frac{- ( - 15 ) - 17}{2 ( - 4 )} : \frac{1}{4}

The solutions to the quadratic equation are:

x = - 4, x = \frac{1}{4}

\frac{x}{4} + 1 = 2

\frac{k}{2 k + 1} + \frac{1}{( 2 k + 1 ) ( 2 k + 3 )}

3 x^{2} - 2 x (x - 4) = x - 12

8 x - 48 = 6 x + 32

0. 9^{3}

What are the solutions to the equation -4x^2-15x+4=0 ?
The solutions to the equation -4x^2-15x+4=0 are x=-4,x= 1/4
Find the zeros of -4x^2-15x+4=0
The zeros of -4x^2-15x+4=0 are x=-4,x= 1/4