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Popular >

|4y+12|<16

Solution

∣ 4 y + 12 ∣ < 16

Solution

- 7 < y < 1

+1

Interval Notation

(- 7, 1)

Solution steps

∣ 4 y + 12 ∣ < 16

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 16 < 4 y + 12 < 16

4 y + 12 > - 16 and 4 y + 12 < 16

y > - 7 and y < 1

Merge Overlapping Intervals

- 7 < y < 1

Popular Examples

simplify i^{103}simplify

i^{103}

factor 2m^2+21m+10 factor

2 m^{2} + 21 m + 10

factor 2xy-6y+xz-3z factor

2 x y - 6 y + x z - 3 z

-7(n+7)=3(2n+1)

- 7 (n + 7) = 3 (2 n + 1)

simplify-9/12 simplify

- \frac{9}{12}

Frequently Asked Questions (FAQ)

What is |4y+12|<16 ?
The solution to |4y+12|<16 is -7<y<1