What are the solutions to the equation W^2+26=14 ?

The solutions to the equation W^2+26=14 are W=2sqrt(3)i,W=-2sqrt(3)i

Find the zeros of W^2+26=14

The zeros of W^2+26=14 are W=2sqrt(3)i,W=-2sqrt(3)i

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W^{2} + 26 = 14

W = 23 i, W = - 23 i

Solution steps

W^{2} + 26 = 14

Move

26

to the right side

W^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

W = - 12, W = - - 12

- 12 = 23 i

- - 12 = - 23 i

W = 23 i, W = - 23 i

a^{2} - 3 a - 154 = 0

x^{2} - 24 x + 144

v^{2} - 7 v = 0

- \frac{4}{4} + 160% + \frac{1}{5}

\frac{7}{12} - \frac{1}{4}

What are the solutions to the equation W^2+26=14 ?
The solutions to the equation W^2+26=14 are W=2sqrt(3)i,W=-2sqrt(3)i
Find the zeros of W^2+26=14
The zeros of W^2+26=14 are W=2sqrt(3)i,W=-2sqrt(3)i