What are the solutions to the equation 2x^2+3x+1=0 ?

The solutions to the equation 2x^2+3x+1=0 are x=-1/2 ,x=-1

Find the zeros of 2x^2+3x+1=0

The zeros of 2x^2+3x+1=0 are x=-1/2 ,x=-1

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2 x^{2} + 3 x + 1 = 0

x = - \frac{1}{2}, x = - 1

Decimal Notation

x = - 0.5, x = - 1

Solution steps

2 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

3^{2} - 4 \cdot 2 \cdot 1 = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 \cdot 2}, x_{2} = \frac{- 3 - 1}{2 \cdot 2}

x = \frac{- 3 + 1}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 3 - 1}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 1

(3 x^{2})^{3}

\frac{x ^{2}}{12} - \frac{4 x}{3} + 5 = 0

7 x + 0 = 2 x + 18 + 2 x + 18

6 x - 4 + 2 x = 4 (5 + 2 x)

(5 r^{3})^{\frac{1}{4}}

What are the solutions to the equation 2x^2+3x+1=0 ?
The solutions to the equation 2x^2+3x+1=0 are x=-1/2 ,x=-1
Find the zeros of 2x^2+3x+1=0
The zeros of 2x^2+3x+1=0 are x=-1/2 ,x=-1