What are the solutions to the equation 16x^2+16=0 ?

The solutions to the equation 16x^2+16=0 are x=i,x=-i

Find the zeros of 16x^2+16=0

The zeros of 16x^2+16=0 are x=i,x=-i

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16 x^{2} + 16 = 0

x = i, x = - i

Solution steps

16 x^{2} + 16 = 0

Move

16

to the right side

16 x^{2} = - 16

Divide both sides by

16

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

4 (6 - 3 x)^{2} + 42 = 43

2 c^{2} + c = 6

- \frac{1}{2} x = 4

5 (- 2 k - 3) + 2 k

- ∣ 6 c ∣ - 2 > - 10

What are the solutions to the equation 16x^2+16=0 ?
The solutions to the equation 16x^2+16=0 are x=i,x=-i
Find the zeros of 16x^2+16=0
The zeros of 16x^2+16=0 are x=i,x=-i