What are the solutions to the equation x^2+34=-11x ?

The solutions to the equation x^2+34=-11x are x=-11/2+i(sqrt(15))/2 ,x=-11/2-i(sqrt(15))/2

Find the zeros of x^2+34=-11x

The zeros of x^2+34=-11x are x=-11/2+i(sqrt(15))/2 ,x=-11/2-i(sqrt(15))/2

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x^{2} + 34 = - 11 x

x = - \frac{11}{2} + i \frac{15}{2}, x = - \frac{11}{2} - i \frac{15}{2}

Solution steps

x^{2} + 34 = - 11 x

Move

11 x

to the left side

x^{2} + 34 + 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 11 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

1 1^{2} - 4 \cdot 1 \cdot 34 : 15 i

x_{1, 2} = \frac{- 11 \pm 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 15 i}{2 \cdot 1}, x_{2} = \frac{- 11 - 15 i}{2 \cdot 1}

x = \frac{- 11 + 15 i}{2 \cdot 1} : - \frac{11}{2} + i \frac{15}{2}

x = \frac{- 11 - 15 i}{2 \cdot 1} : - \frac{11}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = - \frac{11}{2} + i \frac{15}{2}, x = - \frac{11}{2} - i \frac{15}{2}

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\frac{w}{3} \geq 2

(3 - i)^{6}

\frac{h - 50}{5} \geq 1.645

What are the solutions to the equation x^2+34=-11x ?
The solutions to the equation x^2+34=-11x are x=-11/2+i(sqrt(15))/2 ,x=-11/2-i(sqrt(15))/2
Find the zeros of x^2+34=-11x
The zeros of x^2+34=-11x are x=-11/2+i(sqrt(15))/2 ,x=-11/2-i(sqrt(15))/2