What are the solutions to the equation n^2+18n+5200=0 ?

The solutions to the equation n^2+18n+5200=0 are n=-9+sqrt(5119)i,n=-9-sqrt(5119)i

Find the zeros of n^2+18n+5200=0

The zeros of n^2+18n+5200=0 are n=-9+sqrt(5119)i,n=-9-sqrt(5119)i

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n^{2} + 18 n + 5200 = 0

n = - 9 + 5119 i, n = - 9 - 5119 i

Solution steps

n^{2} + 18 n + 5200 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 5200}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 5200 : 25119 i

n_{1, 2} = \frac{- 18 \pm 2 5119 i}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 18 + 2 5119 i}{2 \cdot 1}, n_{2} = \frac{- 18 - 2 5119 i}{2 \cdot 1}

n = \frac{- 18 + 2 5119 i}{2 \cdot 1} : - 9 + 5119 i

n = \frac{- 18 - 2 5119 i}{2 \cdot 1} : - 9 - 5119 i

The solutions to the quadratic equation are:

n = - 9 + 5119 i, n = - 9 - 5119 i

(5 x + 3)^{2} = 16

- 1 < 2 x - 1 \leq 7

\frac{5}{6} - \frac{7}{12}

x^{2} - 64 < 0

\frac{12}{3 + 3}

What are the solutions to the equation n^2+18n+5200=0 ?
The solutions to the equation n^2+18n+5200=0 are n=-9+sqrt(5119)i,n=-9-sqrt(5119)i
Find the zeros of n^2+18n+5200=0
The zeros of n^2+18n+5200=0 are n=-9+sqrt(5119)i,n=-9-sqrt(5119)i