What are the solutions to the equation w^2+w-30=0 ?

The solutions to the equation w^2+w-30=0 are w=5,w=-6

Find the zeros of w^2+w-30=0

The zeros of w^2+w-30=0 are w=5,w=-6

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w^{2} + w - 30 = 0

w = 5, w = - 6

Solution steps

w^{2} + w - 30 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 30) = 11

w_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 1 + 11}{2 \cdot 1}, w_{2} = \frac{- 1 - 11}{2 \cdot 1}

w = \frac{- 1 + 11}{2 \cdot 1} : 5

w = \frac{- 1 - 11}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

w = 5, w = - 6

(8^{\frac{1}{2}})^{3}

\frac{π}{2} - \frac{π}{4}

- 7 (1 - 4 m) = 13 (2 m - 3)

8 1^{2}

n^{2} + 2 n - 15 = 0

What are the solutions to the equation w^2+w-30=0 ?
The solutions to the equation w^2+w-30=0 are w=5,w=-6
Find the zeros of w^2+w-30=0
The zeros of w^2+w-30=0 are w=5,w=-6