What are the solutions to the equation k^2=19 ?

The solutions to the equation k^2=19 are k=sqrt(19),k=-sqrt(19)

Find the zeros of k^2=19

The zeros of k^2=19 are k=sqrt(19),k=-sqrt(19)

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k^{2} = 19

k = 19, k = - 19

Decimal Notation

k = 4.35889 \dots, k = - 4.35889 \dots

Solution steps

k^{2} = 19

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 19, k = - 19

(x + 6)^{2} = 49

y^{2} - 4 = 0

4 x + 6 < 2 x + 1

2 x^{2} < 7 x + 15

x^{2} + 2 x - 24 = 24

What are the solutions to the equation k^2=19 ?
The solutions to the equation k^2=19 are k=sqrt(19),k=-sqrt(19)
Find the zeros of k^2=19
The zeros of k^2=19 are k=sqrt(19),k=-sqrt(19)