What is (x+2)/(x+3)>= (x+1)/(x-2) ?

The solution to (x+2)/(x+3)>= (x+1)/(x-2) is x<-3\lor-7/4 <= x<2

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(x+2)/(x+3)>= (x+1)/(x-2)

\frac{x + 2}{x + 3} \geq \frac{x + 1}{x - 2}

x < - 3 or - \frac{7}{4} \leq x < 2

Interval Notation

(- \infty, - 3) \cup [- \frac{7}{4}, 2)

Decimal Notation

x < - 3 or - 1.75 \leq x < 2

Solution steps

\frac{x + 2}{x + 3} \geq \frac{x + 1}{x - 2}

Rewrite in standard form

\frac{- 4 x - 7}{( x + 3 ) ( x - 2 )} \geq 0

Identify the intervals

x < - 3 or - \frac{7}{4} \leq x < 2

(x - 2)^{2} - 16 y^{2}

x^{4} + 64 x^{2}

2 (3 x + 1) \leq 20

3 x - 7 - 5 x = - 3 x + 2

(10 - 3 i) (10 + 3 i)

What is (x+2)/(x+3)>= (x+1)/(x-2) ?
The solution to (x+2)/(x+3)>= (x+1)/(x-2) is x<-3\lor-7/4 <= x<2