What are the solutions to the equation x^2-14x+36=0 ?

The solutions to the equation x^2-14x+36=0 are x=7+sqrt(13),x=7-sqrt(13)

Find the zeros of x^2-14x+36=0

The zeros of x^2-14x+36=0 are x=7+sqrt(13),x=7-sqrt(13)

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x^{2} - 14 x + 36 = 0

x = 7 + 13, x = 7 - 13

Solution steps

x^{2} - 14 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 36 = 213

x_{1, 2} = \frac{- ( - 14 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 13}{2 \cdot 1} : 7 + 13

x = \frac{- ( - 14 ) - 2 13}{2 \cdot 1} : 7 - 13

The solutions to the quadratic equation are:

x = 7 + 13, x = 7 - 13

3 x + 7 > 19

∣ 9 + x ∣ = 4

2 \leq 2 p - 28

(2^{3} y^{2})^{3}

(\frac{7}{9})^{0}

What are the solutions to the equation x^2-14x+36=0 ?
The solutions to the equation x^2-14x+36=0 are x=7+sqrt(13),x=7-sqrt(13)
Find the zeros of x^2-14x+36=0
The zeros of x^2-14x+36=0 are x=7+sqrt(13),x=7-sqrt(13)