What are the solutions to the equation x^2+2x+11=0 ?

The solutions to the equation x^2+2x+11=0 are x=-1+sqrt(10)i,x=-1-sqrt(10)i

Find the zeros of x^2+2x+11=0

The zeros of x^2+2x+11=0 are x=-1+sqrt(10)i,x=-1-sqrt(10)i

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x^{2} + 2 x + 11 = 0

x = - 1 + 10 i, x = - 1 - 10 i

Solution steps

x^{2} + 2 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 11 : 210 i

x_{1, 2} = \frac{- 2 \pm 2 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 10 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 10 i}{2 \cdot 1}

x = \frac{- 2 + 2 10 i}{2 \cdot 1} : - 1 + 10 i

x = \frac{- 2 - 2 10 i}{2 \cdot 1} : - 1 - 10 i

The solutions to the quadratic equation are:

x = - 1 + 10 i, x = - 1 - 10 i

- 6 x^{2} + 384 = 0

3 x - 4 + 5 \leq 6 - x + 5

- - 18

x^{3} - 4 x^{2} + 3 x > 0

\frac{1}{- \frac{5}{2} + 2}

What are the solutions to the equation x^2+2x+11=0 ?
The solutions to the equation x^2+2x+11=0 are x=-1+sqrt(10)i,x=-1-sqrt(10)i
Find the zeros of x^2+2x+11=0
The zeros of x^2+2x+11=0 are x=-1+sqrt(10)i,x=-1-sqrt(10)i