What are the solutions to the equation 9r^2+6r+1=0 ?

The solutions to the equation 9r^2+6r+1=0 are r=-1/3

Find the zeros of 9r^2+6r+1=0

The zeros of 9r^2+6r+1=0 are r=-1/3

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9 r^{2} + 6 r + 1 = 0

r = - \frac{1}{3}

Decimal Notation

r = - 0.33333 \dots

Solution steps

9 r^{2} + 6 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

r_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

r = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

r = - \frac{1}{3}

The solution to the quadratic equation is:

r = - \frac{1}{3}

- 2 x - 8 \leq 10

5 x^{2} - 25 x + 30 = 0

- 8 (x^{- 3} y^{4})^{- 5}

748

(9 x^{\frac{1}{2}})^{2}

What are the solutions to the equation 9r^2+6r+1=0 ?
The solutions to the equation 9r^2+6r+1=0 are r=-1/3
Find the zeros of 9r^2+6r+1=0
The zeros of 9r^2+6r+1=0 are r=-1/3