What are the solutions to the equation 3x^2+6x=57 ?

The solutions to the equation 3x^2+6x=57 are x=-1+2sqrt(5),x=-1-2sqrt(5)

Find the zeros of 3x^2+6x=57

The zeros of 3x^2+6x=57 are x=-1+2sqrt(5),x=-1-2sqrt(5)

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3 x^{2} + 6 x = 57

x = - 1 + 25, x = - 1 - 25

Decimal Notation

x = 3.47213 \dots, x = - 5.47213 \dots

Solution steps

3 x^{2} + 6 x = 57

Move

57

to the left side

3 x^{2} + 6 x - 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 57 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 57) = 125

x_{1, 2} = \frac{- 6 \pm 12 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 12 5}{2 \cdot 3}, x_{2} = \frac{- 6 - 12 5}{2 \cdot 3}

x = \frac{- 6 + 12 5}{2 \cdot 3} : - 1 + 25

x = \frac{- 6 - 12 5}{2 \cdot 3} : - 1 - 25

The solutions to the quadratic equation are:

x = - 1 + 25, x = - 1 - 25

8 w = 72

12 y^{2} + y - 20

\frac{x}{- 6} = - 7

7 (x + 1) + 3 \geq 6 x + 15

∣ ln (x + 1) ∣ < 1

What are the solutions to the equation 3x^2+6x=57 ?
The solutions to the equation 3x^2+6x=57 are x=-1+2sqrt(5),x=-1-2sqrt(5)
Find the zeros of 3x^2+6x=57
The zeros of 3x^2+6x=57 are x=-1+2sqrt(5),x=-1-2sqrt(5)