What are the solutions to the equation 5x^2+7x-34=0 ?

The solutions to the equation 5x^2+7x-34=0 are x=2,x=-17/5

Find the zeros of 5x^2+7x-34=0

The zeros of 5x^2+7x-34=0 are x=2,x=-17/5

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5 x^{2} + 7 x - 34 = 0

x = 2, x = - \frac{17}{5}

Decimal Notation

x = 2, x = - 3.4

Solution steps

5 x^{2} + 7 x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 34 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 34) = 27

x_{1, 2} = \frac{- 7 \pm 27}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 27}{2 \cdot 5}, x_{2} = \frac{- 7 - 27}{2 \cdot 5}

x = \frac{- 7 + 27}{2 \cdot 5} : 2

x = \frac{- 7 - 27}{2 \cdot 5} : - \frac{17}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{17}{5}

lo g_{3} (\frac{1}{81}) = - 4

q^{2} = 25

3 x + 3 \leq - 6

x^{2} - 6 x - 55 = 0

9 x + 120 = 10 x + 116

What are the solutions to the equation 5x^2+7x-34=0 ?
The solutions to the equation 5x^2+7x-34=0 are x=2,x=-17/5
Find the zeros of 5x^2+7x-34=0
The zeros of 5x^2+7x-34=0 are x=2,x=-17/5