What are the solutions to the equation 3x^2-5x+1=0 ?

The solutions to the equation 3x^2-5x+1=0 are x=(5+sqrt(13))/6 ,x=(5-sqrt(13))/6

Find the zeros of 3x^2-5x+1=0

The zeros of 3x^2-5x+1=0 are x=(5+sqrt(13))/6 ,x=(5-sqrt(13))/6

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3 x^{2} - 5 x + 1 = 0

x = \frac{5 + 13}{6}, x = \frac{5 - 13}{6}

Decimal Notation

x = 1.43425 \dots, x = 0.23240 \dots

Solution steps

3 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 \cdot 1 = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 3}

x = \frac{- ( - 5 ) + 13}{2 \cdot 3} : \frac{5 + 13}{6}

x = \frac{- ( - 5 ) - 13}{2 \cdot 3} : \frac{5 - 13}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 13}{6}, x = \frac{5 - 13}{6}

12 x^{2} - 72 x + 96

4 x - 7 < 41

1. 1^{3}

x^{2} - 3 x = - 2

x^{2} + 16 x + 39

What are the solutions to the equation 3x^2-5x+1=0 ?
The solutions to the equation 3x^2-5x+1=0 are x=(5+sqrt(13))/6 ,x=(5-sqrt(13))/6
Find the zeros of 3x^2-5x+1=0
The zeros of 3x^2-5x+1=0 are x=(5+sqrt(13))/6 ,x=(5-sqrt(13))/6