What is the answer to 3^{|x+1|}-|3^x-1|=3^x+2 ?

The answer to 3^{|x+1|}-|3^x-1|=3^x+2 is x=-2\lor x=0

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3^{|x+1|}-|3^x-1|=3^x+2

3^{∣ x + 1 ∣} - ∣ 3^{x} - 1 ∣ = 3^{x} + 2

x = - 2 or x = 0

Solution steps

3^{∣ x + 1 ∣} - ∣ 3^{x} - 1 ∣ = 3^{x} + 2

Find positive and negative intervals

x < - 1, - 1 \leq x < 0, x \geq 0

Solve the inequality for each interval

x = - 2 or No Solution or x = 0

x = - 2 or x = 0

8 - (7 - 3)^{2}

\frac{1}{2} (16)

1 0^{\frac{8}{5}}

- 1 \leq x < 1

- 7 \leq - 5 + \frac{h}{6}

What is the answer to 3^{|x+1|}-|3^x-1|=3^x+2 ?
The answer to 3^{|x+1|}-|3^x-1|=3^x+2 is x=-2\lor x=0
Solve for x: 3^{|x+1|}-|3^x-1|=3^x+2
The solution is x=-2\lor x=0