What are the solutions to the equation 12x^2+8x-15=0 ?

The solutions to the equation 12x^2+8x-15=0 are x= 5/6 ,x=-3/2

Find the zeros of 12x^2+8x-15=0

The zeros of 12x^2+8x-15=0 are x= 5/6 ,x=-3/2

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12 x^{2} + 8 x - 15 = 0

x = \frac{5}{6}, x = - \frac{3}{2}

Decimal Notation

x = 0.83333 \dots, x = - 1.5

Solution steps

12 x^{2} + 8 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 12 ( - 15 )}{2 \cdot 12}

8^{2} - 4 \cdot 12 (- 15) = 28

x_{1, 2} = \frac{- 8 \pm 28}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 8 + 28}{2 \cdot 12}, x_{2} = \frac{- 8 - 28}{2 \cdot 12}

x = \frac{- 8 + 28}{2 \cdot 12} : \frac{5}{6}

x = \frac{- 8 - 28}{2 \cdot 12} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - \frac{3}{2}

∣ 2 y - 3 ∣ \geq 12

0 = x^{2} - 8 x + 13

2 x + 24 = \frac{2}{7} x

6 x^{2} + 3 x = 0

(- 3)^{3}

What are the solutions to the equation 12x^2+8x-15=0 ?
The solutions to the equation 12x^2+8x-15=0 are x= 5/6 ,x=-3/2
Find the zeros of 12x^2+8x-15=0
The zeros of 12x^2+8x-15=0 are x= 5/6 ,x=-3/2