What is factor 5x^2+19x-4 ?

The solution to factor 5x^2+19x-4 is (5x-1)(x+4)

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factor 5x^2+19x-4

factor

5 x^{2} + 19 x - 4

(5 x - 1) (x + 4)

Solution steps

5 x^{2} + 19 x - 4

Break the expression into groups

= (5 x^{2} - x) + (20 x - 4)

Factor out

x

from

5 x^{2} - x : x (5 x - 1)

Factor out

4

from

20 x - 4 : 4 (5 x - 1)

= x (5 x - 1) + 4 (5 x - 1)

Factor out common term

5 x - 1

= (5 x - 1) (x + 4)

8 n^{3} + 2 n^{2}

(\frac{8}{17})^{2} - (\frac{15}{17})^{2}

\frac{2}{3} \cdot 180

x^{3} \geq x

\frac{n}{2} - 1 < 1