What are the solutions to the equation 3x^2-15x=48-3x ?

The solutions to the equation 3x^2-15x=48-3x are x=2(1+sqrt(5)),x=2(1-sqrt(5))

Find the zeros of 3x^2-15x=48-3x

The zeros of 3x^2-15x=48-3x are x=2(1+sqrt(5)),x=2(1-sqrt(5))

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3 x^{2} - 15 x = 48 - 3 x

x = 2 (1 + 5), x = 2 (1 - 5)

Decimal Notation

x = 6.47213 \dots, x = - 2.47213 \dots

Solution steps

3 x^{2} - 15 x = 48 - 3 x

Move

3 x

to the left side

3 x^{2} - 12 x = 48

Move

48

to the left side

3 x^{2} - 12 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 48 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 48) = 125

x_{1, 2} = \frac{- ( - 12 ) \pm 12 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 5}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 12 5}{2 \cdot 3}

x = \frac{- ( - 12 ) + 12 5}{2 \cdot 3} : 2 (1 + 5)

x = \frac{- ( - 12 ) - 12 5}{2 \cdot 3} : 2 (1 - 5)

The solutions to the quadratic equation are:

x = 2 (1 + 5), x = 2 (1 - 5)

2^{- 5} = \frac{1}{32}

- 2 < x

x - 1 > 1

4 x^{2} + 10 x - 1 = 0

w^{- 3}

What are the solutions to the equation 3x^2-15x=48-3x ?
The solutions to the equation 3x^2-15x=48-3x are x=2(1+sqrt(5)),x=2(1-sqrt(5))
Find the zeros of 3x^2-15x=48-3x
The zeros of 3x^2-15x=48-3x are x=2(1+sqrt(5)),x=2(1-sqrt(5))