What is factor (x^2+x-6)(2x^2+4x) ?

The solution to factor (x^2+x-6)(2x^2+4x) is 2x(x-2)(x+3)(x+2)

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factor (x^2+x-6)(2x^2+4x)

factor

(x^{2} + x - 6) (2 x^{2} + 4 x)

2 x (x - 2) (x + 3) (x + 2)

Solution steps

(x^{2} + x - 6) (2 x^{2} + 4 x)

Factor

x^{2} + x - 6 : (x - 2) (x + 3)

Factor

2 x^{2} + 4 x : 2 x (x + 2)

= (x - 2) (x + 3) \cdot 2 x (x + 2)

= 2 x (x - 2) (x + 3) (x + 2)

\frac{5}{8} + \frac{1}{2}

\frac{125 x ^{3} y ^{6}}{5 x ^{8} y ^{7}}

\frac{1}{x} > 4

(y (1 - y)) - 2 = 0

18 x^{3} - 2 x^{2} + 27 x - 3

What is factor (x^2+x-6)(2x^2+4x) ?
The solution to factor (x^2+x-6)(2x^2+4x) is 2x(x-2)(x+3)(x+2)