What are the solutions to the equation x^2+x+3=0 ?

The solutions to the equation x^2+x+3=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

Find the zeros of x^2+x+3=0

The zeros of x^2+x+3=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

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x^{2} + x + 3 = 0

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

Solution steps

x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 3 : 11 i

x_{1, 2} = \frac{- 1 \pm 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 11 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 11 i}{2 \cdot 1}

x = \frac{- 1 + 11 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{11}{2}

x = \frac{- 1 - 11 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

- 150 = - 4.9 t^{2}

2 x + 16 = 5 x + 4

\frac{1}{1 - \frac{1}{9}}

3 x^{2} - 2 (x^{2} + 4) = 42

- 6 < 3 x - 7 < 11

What are the solutions to the equation x^2+x+3=0 ?
The solutions to the equation x^2+x+3=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2
Find the zeros of x^2+x+3=0
The zeros of x^2+x+3=0 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2